# Find velocity from Power vs position graph

542 views

Power =(force)(velocity)
At x=0 ,
v=1 ,
P=2,
F=(10/3)a
Hence $2=(10/3)a(1)$
$a=(14/10)$
Now at x=10 , P=4
$4=(10/3)(14/10)v$
$v=2$ at x =10
But it is wrong why ?

You are assuming that force and acceleration are constant. They are not constant. So acceleration at $x=10$ is not equal to that at $x=0$.