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Deduce expressions for the intensities $E_1$ and $E_2$ [closed]

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A parallel plate capacitor has two sections. In these sections, areas of
plates are $A_1$ and $A_2$ and distances between the plates are $d_1$ and $d_2$
respectively. The distances between the plates are much smaller than
their linear dimensions. A uniform electric field E that is perpendicular
to the plates is switched on. Neglecting edge effects, deduce expressions
for the intensities $E_1$ and $E_2$ of electric fields established in both the
sections of the capacitor.

My try

closed with the note: Not clear what is being asked
asked Jun 19 in Physics Problems by koolman (4,116 points)
closed Jul 17 by sammy gerbil
"A uniform electric field E that is perpendicular to the plates is switched on." This does not make sense to me. Is this an external field in which the capacitor is placed? So the plates do not become charged, only polarised. Or does it mean that a potential difference is applied to the plates of the capacitor? Does the book provide a solution?
No, the book does not provide any solution
In that case I do not think I can help, because I do not understand how the "switched on" electric field $E$ relates to the problem.

I suggest that you post the question in the chatroom "Problem Solving Strategies." Maybe someone there has seen the problem before, and know what it means.
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