Two masses each of m are attached at mid point B & end point C of massless rod AC which is hinged at A. It is released from horizontal position as shown. Find the force at hinge A when rod becomes vertical .

I tried to conserve energy to find velocity when it is vertical .

That is for mass at B

mgl/2 = (1/2)mv$^2$

From this I got centripetal force when vertical by mv$^2$/(l/2).

Same doing for mass at A .

I got as 2mg in both cases

So total force should be 6mg(including gravitational force .

But the answer given as 28mg/5